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4x^2-21x+26=0
a = 4; b = -21; c = +26;
Δ = b2-4ac
Δ = -212-4·4·26
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-5}{2*4}=\frac{16}{8} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+5}{2*4}=\frac{26}{8} =3+1/4 $
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